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find the perfect square
-6x=3x^2+9

Sagot :

feras119fff

Answer:

[tex] - 6x = 3 {x}^{2} + 9 \\ 3 {x}^{2} + 6x + 9 = 0 \\ {x}^{2} + 2x + 3 = 0 \\ so \\ ether \: x = - 2 \\ or \: x = 1 [/tex]
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