Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

(1/3x) whole square - 2(1/3x)(2/5y)+(2/5y) whole square

I cant simplify this am stuck in this step

Sagot :

sreedevi102

Answer:

You didn't mention if it is to simplify or to factorize. So have done both.

Step-by-step explanation:

[tex]If \ a = \frac{1}{3}x \ , \ b = \frac{2}{5}y , \ then \ the \ expression \ is \ of \ the \ form \ a^2 - 2ab + b^2[/tex] [tex]which \ is \ (a - b)^2[/tex].

So if  you want to expand :

[tex](\frac{1}{3}x)^2 - 2 (\frac{1 \times x}{3})(\frac{2 \times y}{5}) + (\frac{2}{5}y)^2[/tex]  [tex]=\frac{x^2}{9} - \frac{4xy}{15} + \frac{4y^2}{25}[/tex]

If it is to factorize :

[tex](\frac{1}{3}x)^2 - 2 (\frac{1 \times x}{3})(\frac{2 \times y}{5}) + (\frac{2}{5}y)^2 = (\frac{1}{3}x-\frac{2}{5}y)(\frac{1}{3}x - \frac{2}{5}y)=(\frac{1}{3}x - \frac{2}{5}y)^2[/tex]

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.