Answer:
[tex](9\pi - 18)cm^2[/tex]
Step-by-step explanation:
To find the area of this section of the triangle, we will have to find the area of the sector, and then subtract the area of the triangle. To first find the area of the sector of the circle. Remember that the sector of a circle can be found using a proportion of angles. Since there is an angle of 90 degrees in the center. We will take that and divide it by 360 degrees, which is an entire circle. [tex]\frac{90}{360} = \frac{1}{4}[/tex], so the sector is one-quarter of the entire circle. Now find the area of the entire circle which will be [tex]\pi r^{2}[/tex]× [tex]\frac{1}{4}[/tex], where r is 6 since it is the radius of the circle. So therefore the area of the sectore will be a quarter of 36[tex]\pi[/tex], which is 9[tex]\pi[/tex].
Now you must find the area of the triangle with side length 6. Remember, this is an isosceles triangle with sides length of 6 because two of the sides are radii. Also, remember that this is a 90 degree triangle, so the area of the triangle is simply [tex]\frac{6*6}{2}[/tex], which is 18 cm^2.
Now to find the area of just the yellow segment, just take the area of the sector we found, and subtract the area of the triangle. Therefore, the answer is [tex](9\pi - 18)cm^2[/tex]
Hope this helped.
