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PLEASE I NEED THE ANSWER DON'T IGNORE MY QUESTION!!! Solve for X for the following

PLEASE I NEED THE ANSWER DONT IGNORE MY QUESTION Solve For X For The Following class=

Sagot :

Answer:

Fig. 1 :- 7.6

Fig. 2 :- 15

Step-by-step explanation:

We can use Pythagoras theorem to solve for x

[tex]c^{2} =a^{2} +b^{2}[/tex]

Figure 1:

[tex]c^{2} =7^{2} +3^{2}[/tex]

[tex]c^{2} =49+9[/tex]

[tex]c^{2} =58[/tex]

[tex]c=\sqrt{58}[/tex]

[tex]c=7.615773106[/tex]

You can now round your answer:

[tex]c=7.6[/tex]

Figure 2:

[tex]c^{2} =12^{2} +9^{2}[/tex]

[tex]c^{2} =144+81[/tex]

[tex]c^{2} =225[/tex]

[tex]c=\sqrt{225}[/tex]

[tex]c=15[/tex]

I hope this helps :)

Step-by-step explanation:

fig(1)

h=x

p=3

b=7

now,

h^2=p^2+b^2. (by Pythagoras theory)

or, x^2=3^2+7^2

or, x^2=9+49

or, x^2=58

or, x=√58

fig(2)

h=x

p=12

b=9

now,

h^2=p^2+b^2

or, x^2=12^2+9^2

or, x^2=144+81

or, x^2=225

or, x=15