Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
Explanation:
Kinetic Energy has a formula of
[tex]KE=\frac{1}{2}mv^2[/tex] and
Potential Energy has a formula of
PE = mgh. The first 2 problems use the KE formula and the next 2 use the PE formula.
Q1. KE = 16 and v = 4 m/s:
[tex]16=\frac{1}{2}m(4)^2[/tex] and
[tex]\frac{2(16)}{16}=m[/tex] so
m = 2 kg
Q2. mass = 1 kg and v = 10 m/s:
[tex]KE=\frac{1}{2}(1)(10)^2[/tex] so
KE = 50 J
Q3. PE = 40, h = 2, g = 9.8:
40 = m(9.8)(2) and
[tex]\frac{40}{(9.8)(2)}=m[/tex] so
m = 2.0 kg
Q4. mass = 2 kg, g = 9.8 m/s/s, h = 20:
PE = 2(9.8)(20) so
PE = 392 J
**I completely disregarded the rules for sig fig's because your numbers were very inexact**
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.