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Answered

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100 POINT PLEASE HELP QUICK!!!!

100 POINT PLEASE HELP QUICK class=

Sagot :

Answer:

[tex]adjacent = \sqrt{ {50}^{2} - {14}^{2} } = 48 \\ \\ \sin(Q) = \frac{14}{50} = \frac{7}{25} \\ \cos(Q) = \frac{48}{50} = \frac{24}{25} \\ \tan(Q) = \frac{14}{48} = \frac{7}{24} [/tex]

[tex] \sin(R) = \frac{48}{50} = \frac{24}{25} \\ \cos(R) = \frac{14}{50} = \frac{7}{25} \\ \tan(R) = \frac{48}{14} = \frac{24}{7} [/tex]

Base

  • √50²-14²
  • √2500-196
  • √48²
  • 48

Now

  • sinQ=P/H=14/50
  • cosQ=B/H=48/50
  • tanQ=P/B=14/48
  • cotQ=B/P=48/14
  • secQ=H/B=50/48
  • cosecQ=H/P=50/14
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