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Sagot :
[tex] {36}^{2x + 5} = {216}^{x - 1} [/tex]
[tex] {6}^{2(2x + 5)} = {6}^{3(x - 1)} [/tex]
[tex] {6}^{(4x + 10)} = {6}^{(3x - 3)} [/tex]
Since bases i.e 6 are same exponents are equal
4x+10= 3x-3
4x-3x = -3-10
x= -13
Answer:
x = -13
Step-by-step explanation:
36 = 6^2
216 = 6^3
36^(2x + 5) = 6^(2)^(2x + 5)
When taking an exponent to an exponet: multiply the exponents
36^(2x + 5) = 6^(4x + 10)
216^(x - 1) = 6^(3)^(x - 1)
When taking an exponent to an exponet: multiply the exponents
216^(x - 1) = 6^(3x - 3)
-----------------------------
Therefor
6^(4x + 10) = 6^(3x - 3)
Since the bases are the same the exponents are equal
4x + 10 = 3x - 3
Subtract 3x from both sides
x + 10 = -3
subtract 10 from both sides
x = -13
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