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What are the x-intercepts of the equation y=4x^2-16

Sagot :

Answer:

x = ± 2

Step-by-step explanation:

To find the x- intercepts let y = 0 , that is

4x² - 16 = 0 (add 16 to both sides )

4x² = 16 ( divide both sides by 4 )

x² = 4 ( take the square root of both sides )

x = ± [tex]\sqrt{4}[/tex] = ± 2

The x- intercepts are x = - 2 and x = 2

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

View image malmasri25
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