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Sagot :
Answer:
[tex]\text{A. }3, \sqrt{27}, 6,\\\text{B. }8, 15, 17,\\\text{C. }5, 5, \sqrt{50}[/tex]
Step-by-step explanation:
All right triangles must follow the Pythagorean Theorem [tex]a^2+b^2=c^2[/tex] where [tex]c[/tex] is the hypotenuse of the triangle.
Verify:
[tex]3^2+\sqrt{27}^2=6^2\checkmark,\\8^2+15^2=17^2\checkmark,\\5^2+5^2=\sqrt{50}^2\checkmark[/tex]
Answer:
Option : A, B, C
Step-by-step explanation:
To make sure the lengths form sides of a triangle we use Pythagoras theorem:
Square of length of larger side = Sum of square of smaller sides.
[tex](A) 3, \sqrt{27}, 6: => 6^2 = 3^2 + (\sqrt{27})^2[/tex]
[tex]36 = 9 + 27\\36 = 36\\Satisfies \ Pythagoras \ Theorem[/tex]
[tex](B) 8, 15, 17 :=> 17^2 = 15^2 + 8^2[/tex]
[tex]289 = 225 + 64 \\289 = 289 \\Satisfies \ the \ condition[/tex]
[tex](C) 5, 5 , \sqrt{50} :=> (\sqrt{50})^2 = 5^2 +5^2\\[/tex]
[tex]50 = 25 + 25 \\50 = 50\\Satisfies \ the \ condition[/tex]
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