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Identify an equation in slope-intercept form for the line parallel to y = 5x + 2 that passes through (-6, -1). O A. y = 5x – 29 O B. y = 1x+ 1 5 O C. y = 5x + 29 OD. y = -5x - 11​

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Corsaquix

Answer:

[tex]{\text{C. }y=5x+29[/tex]

Step-by-step explanation:

The slope-intercept form of a line is given by [tex]y=mx+b[/tex], where [tex]m[/tex] is the slope of the line and [tex]b[/tex] is the y-intercept.

The slopes of parallel lines are always equal. Therefore, the slope of the equation we want to find will also be [tex]5[/tex]. The equation of the line must be true for any point it passes through. Thus, we can plug in the point [tex](-6,-1)[/tex] to solve:

[tex]y=mx+b,\\-1=5(-6)+b,\\-1=-30+b,\\b=29[/tex]

Thus, the equation of the line is [tex]\boxed{\text{C. }y=5x+29}[/tex]

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