ramrak93
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If P = (-4,-3) and Q = (2, 1) are the
endpoints of the diameter of a circle,
find the equation of the circle.
(x - [?])2 + (y - [ ])2 = [
]​

Sagot :

sreedevi102

Answer:

[tex](x+1)^2 + (y + 1)^2 = 13[/tex]

Step-by-step explanation:

To find the centre of the circle, find the mid - point of PQ :

[tex]Centre =( \frac{x_1+x_2}{2} \ , \ \frac{y_1 + y_2}{2}) = (\frac{-2}{2} \ , \ \frac{-2}{2}) = (-1, -1)[/tex]

Diameter = 2 x Radius , To Find the diameter, find distance between P and Q:

[tex]Distance , PQ = \sqrt{(2 - (-4))^2 + (1 -(-3))^2}[/tex]

                   [tex]= \sqrt{6^2 + 4^2} = \sqrt{36+ 16} = \sqrt{52} = \sqrt{4 \times 13} = 2 \times \sqrt{13}[/tex]

PQ is the diameter , therefore radius :

                                                [tex]r = \frac{1}{2} \times 2 \sqrt{13} = \sqrt{13}[/tex]

Equation of a circle :

                              [tex](x + 1)^2 + (y + 1)^2 = 13[/tex]

Answer:

(x - 1)2 + (y - 1)2 = 13

Step-by-step explanation:

This is the answer for Acellus users

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