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can someone help me on this please
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Can Someone Help Me On This Please class=

Sagot :

osa16

Answer:

The answer is Option A

Step-by-step explanation:

Start by dividing 54 by 6 which will give you 9

then divide b² by b^5 which will give you b³ at the denominator

then a^8÷a^-4

using indices...

=a^8-(-4)

=a^12

at the numerator

put everything together and you'll have...

9a^12/b³

A. [tex] \frac{9 \: {a}^{12} }{ {b}^{3} }[/tex] ✅

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]54 {a}^{8} {b}^{2} \div 6 {a}^{ - 4} {b}^{5} [/tex]

To solve the expression in a simpler way, single out the like terms.

Now, we have

[tex] \frac{54}{6} . \frac{ {a}^{8} }{ {a}^{ - 4} } . \frac{ {b}^{2} }{ {b}^{5} } \\ \\ = 9 \: {a}^{8 - ( - 4)} {b}^{2 - 5} \\ \\ (∵ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} ) \\ \\ = 9 \: {a}^{8 + 4} {b}^{ - 3} \\ \\ = 9 \: {a}^{12} {b}^{ - 3} \\ \\ ( \: or \: ) \\ \\ = \frac{9 \: {a}^{12} }{ {b}^{3} } \\ \\ (∵ {a}^{ - m} = \frac{1}{ {a}^{m} } )[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]

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