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a ball is projected horizontally with a velocity of 5 m per second from the top of a building 19.6 m high how long will the ball take to hit the ground(g=10m/s2)​

Sagot :

Answer:

1.98s

Explanation:

The time taken to hit the ground is given by

h=ut+ 1/2 at^2

but u =0

so we have

h=1/2at^2

making t the subject

t=√2h/g

√2×19.6/10

1.98s

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