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Line l has a slope of −3. The line through which of the following pair of points is perpendicular to l? i will give brainliest for the answer


A. (−4,−3),(−3,−6)
B. (−18,−1),(−3,0)
C. (−6,−4),(−3,−3)
D. (−2,−3),(−3,−6)


Sagot :

Answer:

c. (−6,−4),(−3,−3)

Step-by-step explanation:

a). y2 - y1 / x2 - x1

-6 - (-3) / -3 - (-4)

-3/ 1

= -3

b). y2 - y1 / x2 - x1

0 - (-1) / -3 - (-18)

= 1/15

c). y2 - y1 / x2 - x1

-3 - (-4) / -3 - (-6)

= 1/3

d). y2 - y1 / x2 - x1

-6 - (-3) / -3 - (-2)

3

Answer:

D

Step-by-step explanation:

ALWAYS REMEMBER THIS EQUATION: [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]

Find the slope of answer A

1. [tex]\frac{-6 - -3}{-3 - -4} = \frac{-3}{1}[/tex]

 2. This answer is not perpendicular to "l" because it is equal to -3. (Even if it has a different y-intercept, it will just be parallel, not perpendicular.)

Find the slope of answer B

1. [tex]\frac{0 - -1}{-3 - -18} = \frac{1}{15}[/tex]

 2. This answer is not perpendicular to "l".

Find the slope of answer C

1. [tex]\frac{-3 - -4}{-6--2} = \frac{1}{-4}[/tex]

 2. This answer is not perpendicular to "l".

Find the slope of answer D

1. [tex]\frac{-6 - -3}{-3 - -2} = \frac{-3}{-1}[/tex]

 2. This answer is perpendicular to "l" because 3 is the inverse of -3.