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A 100 m2hay shed is to be extended to give 475 m2of oor space in total, as shown. All angles are right angles. Find the value of x.

Sagot :

Answer:

[tex]x = 15.[/tex]

Step-by-step explanation:

Given

See attachment for floor space

Required

Find x

The floor can be partitioned into three space.

The dimension and the area of each space is:

Dimension: 10 by 10

[tex]A_1 = 10* 10 = 100[/tex]

Dimension: 10 by x

[tex]A_2 = 10* x = 10x[/tex]

Dimension: x by x

[tex]A_3 = x* x=x^2[/tex]

So, the total area is:

[tex]Area =100 +10x + x^2[/tex]

Given that:

[tex]Area = 475[/tex]

So, we have:

[tex]100+10x+x^2 =475[/tex]

Rewrite as:

[tex]x^2 +10x+100-475=0[/tex]

[tex]x^2 +10x-375=0[/tex]

Expand

[tex]x^2 + 25x -15x -375 = 0[/tex]

Factorize

[tex]x(x + 25) -15(x +25) = 0[/tex]

Factor out x + 25

[tex](x+25)(x-15)=0[/tex]

Solve:

[tex]x = -25\ or\ x = 15[/tex]

x cannot be negative; So:

[tex]x = 15.[/tex]

View image MrRoyal