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A camera and a case cost 100 dollars. If the camera cost 90 more dollars than the case. How much does the case cost.

Sagot :

SDCInfinity

Answer:

Cost of case = $5

Step-by-step explanation:

x = cost of camera and y = cost of case

x = y + 90

x + y = 100

y + 90 + y = 100

2y = 10

y = 5

x = y + 90

x = 5 + 90

x = 95

Therefore, the cost of the camera is $95 and the cost of the case is $5.

The cost of case is 5 dollars.

What is the equation?

The equation is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is equal.

Let,

Cost of camera = a and

Cost of case = b

Given that, camera and a case cost 100 dollars

a + b = 100

Since, the camera cost 90 more dollars than the case

So, a = b + 90

Substitute the value in the equation a + b = 100

b + 90 + b = 100

2b = 10

Divided by 2 both the sides

b = 5

Substitute the value of b in equation

a = b+ 90

a = 5 + 90

a = 95

So, the cost of the camera is $95 and the cost of the case is $5.

Hence, the cost of the case is 5 dollars.

Learn more about equation here:

brainly.com/question/10413253

#SPJ2

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