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Sagot :
There are two solutions for the triangle DEF: ∠ D₁ ≈ 68.3°, ∠ D₂ ≈ 111.7°.
How to find all possible values of a triangle by law of sines
In this question we have a triangle with two known sides and a known angle. By the law of sines we find the possible values of the angle D:
410/sin 120° = 440/sin D
Please notice that the sum of the internal angles of triangles equals 180°. Then,
sin D = (440/410) · sin 120°
sin D ≈ 0.929
There are two solutions for the triangle DEF: ∠ D₁ ≈ 68.3°, ∠ D₂ ≈ 111.7°.
To learn more on law of sines: https://brainly.com/question/17289163
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