Answer:
-1.6 × 10⁻⁹ z
Explanation:
To attempt this type of question, we need to first divide each charge present in the question with the smallest one.
i.e.
[tex]A = \dfrac{-4.8 \times 10^{-9}}{-4.8 \times 10^{-9}}= 1[/tex]
[tex]B = \dfrac{-9.6 \times 10^{-9}}{-4.8 \times 10^{-9}}= 2[/tex]
[tex]C= \dfrac{-6.4 \times 10^{-9}}{-4.8 \times 10^{-9}}= 1.33[/tex]
[tex]D= \dfrac{-12.8 \times 10^{-9}}{-4.8 \times 10^{-9}}= 2.67 \simeq 3[/tex]
The next thing to do is to multiply each obtained value with the highest integer
A = 1 × 3 = 3
B = 2 × 3 = 6
C = 1.33 × 3 = 3.99
D = 3 × 3 = 9
Finally, we divide each charge by the result from above.
[tex]A = \dfrac{-4.8 \times 10^{-9}}{3}= -1.6 \times 10^{-9}[/tex]
[tex]B = \dfrac{-9.6 \times 10^{-9}}{6}= -1.6\times 10^{-9}[/tex]
[tex]C= \dfrac{-6.4 \times 10^{-9}}{3.99}= -1.6\times 10^{-9}[/tex]
Thus, we can therefore easily conclude that the charge in zorgs (z) is:
-1.6 × 10⁻⁹ z
