Answered

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What volume of 6.49 MHCl is needed to prepare 2.11 L of 1.07 MHCl? Your answer should have three significant figures.

Sagot :

dsdrajlin

Answer:

0.348 L

Explanation:

Step 1: Given data

  • Concentration of the concentrated solution (C₁): 6.49 M
  • Volume of the concentrated solution (V₁): ?
  • Concentration of the dilute solution (C₂): 1.07 M
  • Volume of the dilute solution (V₂): 2.11 L

Step 2: Calculate the volume of the concentrated solution

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.07 M × 2.11 L / 6.49 M = 0.348 L

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