Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Part A
A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is replaced before the second marble is drawn, what is P(blue second | green first)?
Part B
If the first marble is not replaced before the second marble is drawn, what is P(blue second | green first)?

Sagot :

francocanacari

Answer:

If the first marble is replaced before the second marble is drawn, the probability of P is 24%; while if the first marble is not replaced before the second marble is drawn, the probability of P is 26.66%.

Step-by-step explanation:

Since a bag contains 4 blue and 6 green marbles, and two marbles are selected at random from the bag, to determine, if the first marble is replaced before the second marble is drawn, what is P (blue second | green first) and , if the first marble is not replaced before the second marble is drawn, what is P (blue second | green first) the following calculations must be performed:

Blue = 4/10

Green = 6/10

A) 6/10 x 4/10 = 0.24

B) 6/10 x 4/9 = 0.2666

Therefore, if the first marble is replaced before the second marble is drawn, the probability of P is 24%; while if the first marble is not replaced before the second marble is drawn, the probability of P is 26.66%.

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.