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Dhani has 4 cards numbered 1 through 4. He removes 2 cards at random and adds their values.

What is the probability that the sum is less than or equal to 5?
7/12
2/3
3/5
3/4


Sagot :

Answer:

[tex]2/3[/tex]

Step-by-step explanation:

The total number of sums (not distinct) is [tex]4\cdot 3=12[/tex], because we're removing without replacement.

Count the sums that fit the stipulation (sum [tex]\leq[/tex] 5):

[tex]1,2,\\2,1\\1,3\\3,1\\1, 4\\4, 1\\2, 3, \\3,2[/tex]

There are 8 sums that work. Therefore, the desired answer is [tex]\frac{8}{12}=\boxed{\frac{2}{3}}[/tex]