Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Given:
Area of a rectangle = [tex]x^3-5x^2+3x-15[/tex]
Width of rectangle = [tex]x^2+3[/tex]
To find:
The length of the rectangle.
Solution:
The area of a rectangle is:
[tex]A=l\times w[/tex]
Where, l is length and w is the width.
It is can be written as:
[tex]\dfrac{A}{w}=l[/tex]
[tex]l=\dfrac{A}{w}[/tex]
Putting [tex]A=x^3-5x^2+3x-15[/tex] and [tex]w=x^2+3[/tex], we get
[tex]l=\dfrac{x^3-5x^2+3x-15}{x^2+3}[/tex]
[tex]l=\dfrac{x^2(x-5)+3(x-5)}{x^2+3}[/tex]
[tex]l=\dfrac{(x^2+3)(x-5)}{x^2+3}[/tex]
[tex]l=x-5[/tex]
Therefore, the length of the rectangle is [tex]x-5[/tex].
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
