Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Given:
Area of a rectangle = [tex]x^3-5x^2+3x-15[/tex]
Width of rectangle = [tex]x^2+3[/tex]
To find:
The length of the rectangle.
Solution:
The area of a rectangle is:
[tex]A=l\times w[/tex]
Where, l is length and w is the width.
It is can be written as:
[tex]\dfrac{A}{w}=l[/tex]
[tex]l=\dfrac{A}{w}[/tex]
Putting [tex]A=x^3-5x^2+3x-15[/tex] and [tex]w=x^2+3[/tex], we get
[tex]l=\dfrac{x^3-5x^2+3x-15}{x^2+3}[/tex]
[tex]l=\dfrac{x^2(x-5)+3(x-5)}{x^2+3}[/tex]
[tex]l=\dfrac{(x^2+3)(x-5)}{x^2+3}[/tex]
[tex]l=x-5[/tex]
Therefore, the length of the rectangle is [tex]x-5[/tex].
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
