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a body of mass 8 kg is acted upon by the two perpendicular forces of 16 Newton and 12 Newton find the magnitude and direction of the acceleration of the body​

Sagot :

body of mass m is 5 kg

R=

(8)

2

+(−16

2

)=

64+36

=10N

θis angle made by force of 8 N

θ=tan

−1

(−6/8)=−36.87

0

the negative sign indicates theta clockwise direction respect to the force of magnitude 8N

force is m X a

a=f/m=10/5=2ms

−2

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