jacinta57
Answered

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Solve for x
[tex]8 {}^{2 + x} + 2 {}^{3x} = 32 {}^{ \frac{1}{2} } [/tex]
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Sagot :

aprecious224

Answer:

8^2+x + 2^ 3x = 32^ 1/2

2^3(2+x) + 2^3x = 2^5^1/2

All two's will cancel out

3(2+x) + 3x = 5^1/2

6+3x + 3x = 5^1/2

6 +6x = 2.23

6x = 2.23 - 6

6x = -3.77

x = -3.77÷ 6

x = -0.63

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