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Aina builds a cube model out of manila cards. If the volume of the constructed cube is (2+3p) ³ cm³, find the total surface area of the cube in terms of p.

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Sagot :

Given:

The volume of a cube = [tex](2+3p)^3\ \text{cm}^3[/tex]

To find:

The total surface area of the cube in terms of p.

Solution:

Volume of a cube is:

[tex]V=a^3[/tex]            ...(i)

Where, a is the side length.

It is given that,

[tex]V=(2+3p)^3\ \text{cm}^3[/tex]         ...(ii)

On comparing (i) and (ii), we get

[tex]a=2+3p\text{ cm}[/tex]

Now, the total surface area of a cube is:

[tex]A=6a^2[/tex]

Where, a is the side length.

Putting [tex]a=2+3p[/tex], we get

[tex]A=6(2+3p)^2[/tex]

Therefore, the total surface area of the cube in terms of p is [tex]6(2+3p)^2\ \text{cm}^2[/tex].