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Need Help Pls Explain class=

Sagot :

Given:

The graph of a line.

To find:

The equation of the line.

Solution:

From the given graph, it is clear that the line passes through the points (0,-2) and (-6,8). So, the equation of the line is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-(-2)=\dfrac{8-(-2)}{-6-0}(x-0)[/tex]

[tex]y+2=\dfrac{10}{-6}x[/tex]

[tex]y+2=-\dfrac{5}{3}x[/tex]

Subtract 2 from both sides.

[tex]y=-\dfrac{5}{3}x-2[/tex]

Therefore, the equation of the line is [tex]y=-\dfrac{5}{3}x-2[/tex].