Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A sled is moving down a steep hill in a straight line. At time ts, the
acceleration of the sled is ams-2 where a = 1/500(20t^2-t^3), 0 < t < 20. When t = 0
the sled is at rest at the top of the hill. Find the distance the sled travels in
the first 10 s of its motion.

Sagot :

MrRoyal

Acceleration is the rate of change of velocity over time

The sled travels 100 meters in the first 10 seconds of its motion

How to determine the distance

The acceleration function is given as:

[tex]a = \frac 1{500}(20t^2 - t^3)[/tex]

When t = 10, we have:

[tex]a = \frac 1{500}(20*10^2 - 10^3)[/tex]

[tex]a = 2[/tex]

The distance at 10 seconds is then calculated as;

[tex]S = ut +\frac 12 at^2[/tex]

Where:

u = initial velocity = 0

So, we have:

[tex]S = 0 *10 +\frac 12 * 2 * 10^2[/tex]

[tex]S =100[/tex]

Hence, the sled travels 100 meters in the first 10 seconds of its motion

Read more about acceleration at:

https://brainly.com/question/605631

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.