modiriphenyo
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what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

Sagot :

Answer:

The horizontal component of the vector is approximately -16.07

The vertical component of the vector is approximately 19.15

Explanation:

A vector quantity is a quantity that posses both magnitude and direction specifications

The magnitude of the given vector, R = 25 units

The direction of the vector, θ = 130°

Therefore the location of the vector, starting from the origin of the Cartesian plane, is in the second quadrant having an angle of 180° - 130° = 50° to the horizontal

Given that the x-coordinate  is negative in the second quadrant, we have;

The horizontal component of the vector, Rₓ = The x-coordinate of the vector = R×cos(θ)

∴ The horizontal component of the vector, Rₓ = 25 × cos(130°) = -25 × cos(50°) ≈ -16.07

The horizontal component of the vector, Rₓ ≈ -16.07

The vertical component of the vector, [tex]R_y[/tex] = The y-coordinate of the vector = R×sin(θ)

∴ The vertical component of the vector, [tex]R_y[/tex] = 25 × sin(130°) ≈ 19.15

The vertical component of the vector, [tex]R_y[/tex] ≈ 19.15

The vector can be resolved as R = -16.07·i + 19.15·j

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