Answer:
The horizontal component of the vector ≈ -16.06
The vertical component of the vector ≈ 19.15
Explanation:
The magnitude of the vector, [tex]\left | R \right |[/tex] = 25 units
The direction of the vector, θ = 130°
Therefore, we have;
The horizontal component of the vector, Rₓ = [tex]\left | R \right |[/tex] × cos(θ)
∴ Rₓ = 25 × cos(130°) ≈ -16.06
The horizontal component of the vector, Rₓ ≈ -16.06
The vertical component of the vector, R[tex]_y[/tex] = [tex]\left | R \right |[/tex] × sin(θ)
∴ R[tex]_y[/tex] = 25 × sin(130°) ≈ 19.15
The vertical component of the vector, R[tex]_y[/tex] ≈ 19.15
(The vector, R = Rₓ + R[tex]_y[/tex]
[tex]\underset{R}{\rightarrow}[/tex] = Rₓ·i + R[tex]_y[/tex]·j
∴ [tex]\underset{R}{\rightarrow}[/tex] ≈ -16.07·i + 19.15j)
