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Sagot :
[tex]vol. \: of \: cone = \frac{1}{3} \pi \times r ^{2} \times h[/tex]
r = radius
h = height of cone
radius = 5.5÷2
= 2.75
vol. of mold = 1/3π × (2.75)^2 × 15
= 118.79 (5sf)
= 118.8 (nearest tenth)
Answer:
118.8 cubic inches
Step-by-step explanation:
volume of a cone is
[tex]vol \: = \frac{1}{3} \times \pi \times \frac{ {d}^{2} }{4} \times h[/tex]
where d is base diameter and
h is cone height.
hence
[tex]vol \: = \frac{1}{3} \times \pi \times \frac{ {5.5}^{2} }{4} \times 15 \\ = \pi \times \frac{30.25}{4} \times 5 \\ = 118.8 \: cu \: in[/tex]
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