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The rock falls from the distance of 15 m before it hits the water. Calculate its kinetic energy just before hitting the water. Show your working

Sagot :

mvschx

Answer:

8.57m

Explanation:

v²=u²+2as

then1/2mv²

View image mvschx

Answer:

[tex]k.e = \frac{1}{2} m {v}^{2} \\ {v}^{2} = {u}^{2} + 2gs \\ {v}^{2} = 0 + (2 \times 9.8 \times 15) \\ v = 17.1 \: m {s}^{ - 1} \\ k.e = \frac{1}{2} \times m \times {17.1}^{2} \\ = 147m \: joules \\ m \: is \: mass[/tex]

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