Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Consider the following time series. t 1 2 3 4 5 yt 6 10 8 13 15
(a) Choose the correct time series plot. (i) (ii) (iii) (iv) What type of pattern exists in the data?
(b) Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series. If required, round your answers to two decimal places. y-intercept, b0 = 4.1 Slope, b1 = 2.1 MSE = ????
(c) What is the forecast for t = 6? If required, round your answer to one decimal place. 16.7 I know how to do it all but the MSE.

Sagot :

fichoh

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

t __1 2 3 4 5

yt_ 6 10 8 13 15

Using technology to produce a linear model :

The linear model obtained shows a positive linear pattern exist for the time series data :

The parameters for the line that minimizes MSE for the then series is :

y = 2.1t + 4.1

Where, slope = 2.1 ; intercept = 4.1

The mean squared error :

Sum of squared estimate of error = 9.1

Mean squared error = √9.1

Mean squared error = 3.02

Forecast for t = 6

y = 2.1t + 4.1

y = 2.1*6 + 4.1

y = 12.6 + 4.1

y = 16.7

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.