Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A sample of Kr gas is observed to effuse through a porous barrier in 3.79 minutes. Under the same conditions, the same number of moles of an unknown gas requires 2.66 minutes to effuse through the same barrier. The molar mass of the unknown gas is________ g/mol.

Sagot :

okpalawalter8

Answer:

[tex]M'=41.3g/mol[/tex]

Explanation:

From the question we are told that:

Time Through first barrier [tex]T_1=3.79min[/tex]

Time Through second barrier [tex]T_2=2.66min[/tex]

Generally the Grahams Law equation for   time of diffusion is mathematically given by

 [tex]T=K\sqrt{M}[/tex]

Where

M=Mass Number of Kr

 [tex]M=83.8[/tex]

Therefore

 [tex]{T}{\sqrt{M}={T}{\sqrt{M'}[/tex]

 [tex]{3.79}{\sqrt{83.8}={2.66}{\sqrt{M'}[/tex]

 [tex]M'=0.645[/tex]

 [tex]M'=41.3g/mol[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.