Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Assuming no other changes, what is the effect of doubling only the concentration of the alkyl halide in the above SN2 reaction?
A) no change
B) triples the rate
C) rate is halved
D) doubles the rate
E) quadruples the rate

Sagot :

Answer:

D) doubles the rate

Explanation:

The given reaction is :

[tex]$CH_3Br + OH^- \rightarrow CH_3OH+Br^-$[/tex]

For the [tex]SN^2[/tex] reaction, the rate of reaction depends upon the concentration of both the [tex]$\text{alkyl halide}$[/tex] as well as the [tex]\text{nucleophile.}[/tex]

That is the rate = [tex]$k[CH_3Br][OH^-]$[/tex]

Now if the [tex]$[CH_3Br]$[/tex] becomes [tex]$2[CH_3Br]$[/tex], then the rate becomes double.

So the rate' is :

= [tex]$2k[CH_3Br][OH^-]$[/tex]

= 2 x rate

Therefore, the answer is (D) doubles the rate.

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.