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Sagot :
Answer:
D) doubles the rate
Explanation:
The given reaction is :
[tex]$CH_3Br + OH^- \rightarrow CH_3OH+Br^-$[/tex]
For the [tex]SN^2[/tex] reaction, the rate of reaction depends upon the concentration of both the [tex]$\text{alkyl halide}$[/tex] as well as the [tex]\text{nucleophile.}[/tex]
That is the rate = [tex]$k[CH_3Br][OH^-]$[/tex]
Now if the [tex]$[CH_3Br]$[/tex] becomes [tex]$2[CH_3Br]$[/tex], then the rate becomes double.
So the rate' is :
= [tex]$2k[CH_3Br][OH^-]$[/tex]
= 2 x rate
Therefore, the answer is (D) doubles the rate.
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