Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Arrange the following molecules in order of decreasing polarity of their bonds.

a. PBr3
b. SF2
c. H2O
d. NCl3

Sagot :

ajeigbeibraheem

Answer:

SF2 > H2O > PBr3 > NCl3

Explanation:

Compare the electronegativity values for the atoms and classify the nature of the bonding based on the electronegativity difference.

P has an electronegativity of 2.1, while Br has an electronegativity of 2.96. The difference is 0.86, indicating that these atoms will form covalent bonds.

S has an electronegativity of 2.58 while F has an electronegativity of 4.0. The difference is 1.42, indicating that these atoms will form polar covalent bonds.

O has an electronegativity of 3.5 while H has an electronegativity of 2.1. The difference is 1.4, indicating that these atoms will form polar covalent bonds.

N has an electronegativity of 3.04, whereas Cl has an electronegativity of 3.5. This difference of 0.46 indicates that these atoms will form covalent bonds.

We know that the greater the electronegativity, the higher the polarity. In decreasing order of polarity, we have:

SF2 > H2O > PBr3 > NCl3

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.