Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer:
The k value is [tex]k = 0.0015[/tex]
Step-by-step explanation:
Population:
The population P(in thousands), of the city, in t years after 2000, is given by the following equation:
[tex]P(t) = 160.4e^{kt}[/tex]
In 2007, the population of the city was about 162,075.
This means that [tex]P(7) = 162.075[/tex], that is, when [tex]t = 7, P(t) = 162.075[/tex]
Find the k value
[tex]P(t) = 160.4e^{kt}[/tex]
[tex]162.075 = 160.4e^{7k}[/tex]
[tex]e^{7k} = \frac{162.075}{160.4}[/tex]
[tex]\ln{e^{7k}} = \ln{\frac{162.075}{160.4}}[/tex]
[tex]7k = \ln{\frac{162.075}{160.4}}[/tex]
[tex]k = \frac{\ln{\frac{162.075}{160.4}}}{7}[/tex]
[tex]k = 0.0015[/tex]
The k value is [tex]k = 0.0015[/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
