Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

The population P (in thousands) of a certain city from 2000 through 2014 can be modeled by P = 160.4ekt, where t represents the year, with t = 0 corresponding to 2000. In 2007, the population of the city was about 162,075. Find the k value

Sagot :

Answer:

The k value is [tex]k = 0.0015[/tex]

Step-by-step explanation:

Population:

The population P(in thousands), of the city, in t years after 2000, is given by the following equation:

[tex]P(t) = 160.4e^{kt}[/tex]

In 2007, the population of the city was about 162,075.

This means that [tex]P(7) = 162.075[/tex], that is, when [tex]t = 7, P(t) = 162.075[/tex]

Find the k value

[tex]P(t) = 160.4e^{kt}[/tex]

[tex]162.075 = 160.4e^{7k}[/tex]

[tex]e^{7k} = \frac{162.075}{160.4}[/tex]

[tex]\ln{e^{7k}} = \ln{\frac{162.075}{160.4}}[/tex]

[tex]7k = \ln{\frac{162.075}{160.4}}[/tex]

[tex]k = \frac{\ln{\frac{162.075}{160.4}}}{7}[/tex]

[tex]k = 0.0015[/tex]

The k value is [tex]k = 0.0015[/tex]