Answered

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Gloria set aside $100 to buy school lunches for the year. Each school lunch cost $2. The inequality 100 – 2x < 20 can be used to find the number of school lunches Gloria can buy before she has less than $20 left. What is the solution to this inequality?

Sagot :

Peepeepoopoo6999

Answer:

she would be able to buy 40 lunches

Step-by-step explanation:

Subtract  100  from both sides of the inequality

Divide each term by   −2  and simplify.

The solution to the inequality 100 – 2x < 20 is x > 40

How to find solution to an inequality?

She set aside $100 to buy school lunches for the year. Each school lunch cost $2.

Therefore, the inequality can be used to find the number of school lunches Gloria can buy before she has less than $20 left.

100 – 2x < 20

The solution of the inequality is as follows;

100 – 2x < 20

subtract 100 from both sides

100 - 100 - 2x < 20 - 100

-2x < - 80

divide both sides by -2

x > 40

learn more on inequality here: https://brainly.com/question/11872626

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