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A researcher uses an independent-measures t test to evaluate the mean difference between two treatments and obtains t(12) = 4.00. If the researcher had used an ANOVA to evaluate the data, what F-ratio would be obtained?

a. F(1, 11) = 2.00
b. F(1, 12) = 16.00
c. F(1, 12) = 2.00
d. F(1, 11) = 16.00


Sagot :

Answer:

B). F(1, 12) = 16.00

Step-by-step explanation:

'ANOVA' is a measure employed for 'analysis of a variance' in a given set of data of treatments or populations. While t-test helps in comparing their means.

As per the question, the F-ratio using ANOVA would be 'F(1, 12) = 16.00.' In order to calculate the variances, the distinction among the samples. The б^2 denotes the difference of representative means which is augmented by n(in case of samples being same). So, the ratio of F(1, 12) would be б^2 i.e. 4^2 = 16 since the sample sizes are distinct. Thus, option B is the correct answer.