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Write the equation of a line that is perpendicular to y =(1/2)x - 5 and passes through point (-6,2)

Sagot :

Answer: y=-2x-10

Work:
m=(1/2)
m perpendicular= -2
2=-2(-6)+b
b=-10

Explanation: the standard form of the equation of a line is y=mx+b, find the y-int and perpendicular slope.
solaric

Answer:

y=-2x-10

Step-by-step explanation:

Let us start with a general slope-intercept equation, y=mx+b, where m represents the slope, b represents the y-intercept, and the y and x represents the coordinates the line passes through.

Therefore, the slope of our line

[tex]y=\frac{1}{2}x-5[/tex]

is 0.5

We also know that the perpendicular slope is simply the negative reciprocal of the current slope. We know have:

[tex]-\frac{2}{1} =\\-2[/tex]

Now, let us find the y intercept. We can plug in the x and y values using the given coordinate (–6,2).

[tex]y=-2x+b\\2=-2*(-6)+b\\2=12+b\\b=-10[/tex]

Now, we can write our equation:

[tex]y=-2x-10[/tex]

I hope this helps! Let me know if you have any questions :)

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