Answered

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Find the 66th term of the arithmetic sequence -28,-45,-62

Sagot :

Answer:

Using the formula

an = a of 1 + (n-1)(d)

an = -28 + (n-1)(-17)

simplify

an = -17n - 11

Now that we have the formula, we just plug in 66 for n

a66 = -17(66) - 11

a66 = -1133

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