Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A store manager can spend at most $1,000 a day for operating costs and payroll. It costs $100 each day to operate the store and $30 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day, at MOST.


30x + 100 < 1000


A. X > 30

B. X > 33

C. X < 33

D. X < 30

Sagot :

abidemiokin

Answer:

x < 30

Step-by-step explanation:

Given the inequality expression that denotes the statement as;

30x+100 < 1000

Subtract 100 from both sides

30x + 100 - 100 <1000 - 100

30x < 900

Divide both sides by 30

30x/30 < 900/30

x < 30

Hence the required solution is x < 30

onyebuchinnaji

The number of employee the manager can afford a day is x < 30.

The given parameters:

  • Amount spent a day for operating cost = $1,000
  • The operating cost of the store, = $100 per day
  • Amount paid to the employee = $30 per day

The inequality of the number of employee the manager can afford a day is calculated as follows;

30x + 100 < 1000

collect similar terms together;

30x < 1000 - 100

30x < 900

divide both sides of the equation by 30;

[tex]x <\frac{900}{30} \\\\x <30[/tex]

Thus, the number of employee the manager can afford a day is x < 30.

Learn more about solution to inequality here: https://brainly.com/question/24372553

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.