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Convert standard form to vertex form then identify the vertex

-2x^2 - 8x + 3


Sagot :

Answer:

vertex point at (-2|11)

f(x)=-2*((x+2)^2+1*-11/2) (simplified)

Step-by-step explanation:

f(x)=-2*x^2+-8*x+3  

f(x)=-2*(x^2+4*x+-3/2) ( Factor out )

f(x)=-2*(x^2+4*x+(2)^2+-1*(2)^2+-3/2) ( Complete the square )

f(x)=-2*((x+2)^2+-1*(2)^2+-3/2) ( Use the binomial formula )

hope this helped, I didn't get much to work with so if i'm wrong i'm sorry

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