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Triangle PQR is similar to triangle XYZ. The length of PQ is one-half the length of XY. THe length of RP is 2 cm. Which proportion can be used to find the length of ZX?

Sagot :

Answer:

[tex]ZX = 4cm[/tex]

Step-by-step explanation:

Given

[tex]\triangle PQR[/tex] similar to [tex]\triangle XYZ[/tex]

[tex]PQ = \frac{1}{2}XY[/tex]

[tex]RP = 2cm[/tex]

Required

Find ZX

[tex]\triangle PQR[/tex] similar to [tex]\triangle XYZ[/tex] implies that, the following sides are similar

[tex]PQ \to XY[/tex]

[tex]QR \to YZ[/tex]

[tex]RP \to ZX[/tex]

To find ZX, we make use of the following equivalent ratio

[tex]PQ : XY = RP : ZX[/tex]

Where

[tex]PQ = \frac{1}{2}XY[/tex]

[tex]RP = 2cm[/tex]

So, we have:

[tex]\frac{1}{2}XY : XY = 2cm : ZX[/tex]

Express as fraction

[tex]\frac{\frac{1}{2}XY }{ XY }= \frac{2cm }{ ZX}[/tex]

[tex]\frac{1}{2}= \frac{2cm }{ ZX}[/tex]

Make ZX the subject

[tex]ZX = 2 * 2cm[/tex]

[tex]ZX = 4cm[/tex]