Answer:
[tex]ZX = 4cm[/tex]
Step-by-step explanation:
Given
[tex]\triangle PQR[/tex] similar to [tex]\triangle XYZ[/tex]
[tex]PQ = \frac{1}{2}XY[/tex]
[tex]RP = 2cm[/tex]
Required
Find ZX
[tex]\triangle PQR[/tex] similar to [tex]\triangle XYZ[/tex] implies that, the following sides are similar
[tex]PQ \to XY[/tex]
[tex]QR \to YZ[/tex]
[tex]RP \to ZX[/tex]
To find ZX, we make use of the following equivalent ratio
[tex]PQ : XY = RP : ZX[/tex]
Where
[tex]PQ = \frac{1}{2}XY[/tex]
[tex]RP = 2cm[/tex]
So, we have:
[tex]\frac{1}{2}XY : XY = 2cm : ZX[/tex]
Express as fraction
[tex]\frac{\frac{1}{2}XY }{ XY }= \frac{2cm }{ ZX}[/tex]
[tex]\frac{1}{2}= \frac{2cm }{ ZX}[/tex]
Make ZX the subject
[tex]ZX = 2 * 2cm[/tex]
[tex]ZX = 4cm[/tex]