cejah0719p2m0qz
Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

HELP ASAP NEED THE ANSWER LIKE RIGHT NOW 100 POINTS AND WILL GIVE BRAINLIEST

A school fair ticket costs $8 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who went to the fair was 30, and the total money collected was $100. Which of the following options represents the number of children and the number of adults who attended the fair that day, and the pair of equations that can be solved to find the numbers?

20 children and 10 adults
Equation 1: a + c = 30
Equation 2: 8a + c = 100
10 children and 20 adults
Equation 1: a + c = 30
Equation 2: 8a − c = 100
10 children and 20 adults
Equation 1: a + c = 30
Equation 2: 8a + c = 100
20 children and 10 adults
Equation 1: a + c = 30
Equation 2: 8a − c = 100

Sagot :

wegnerkolmp2741o

Answer:

a + c = 30

8a + c = 100

a=10, c= 20

Step-by-step explanation:

cost = 8a + 1c  since it is 8 dollars for adult and 1 for child where a is the number of adults and c is the number of children

a+c = 30  since we know that 30 adults and children went

100 = 8a + 1c   and it cost 100 dollars

Let c =30 -a

100 = 8a + (30-a)

100 = 7a +30

Subtract 30 from each side

70 = 7a

Divide by 7

10 =a

Then a+c = 30

10+c = 30

c = 30-10

c = 20

mhlangatania04

Answer:

eqn1 : a +c=30

eqn2: 8a+c=100

20 children and 10 adults

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.