Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A train starting from rest moves with a uniform acceleration of 0.2 ms-2 for 5 minutes. Calculate the final velocity and the distance travelled in this time.

Sagot :

asuwafohjames

Answer:

Final velocity = 60 m/s

Distance travelled = 9000 m

Explanation:

Applying,

For Final velocity,

v = u+at ............... Equation 1

Where v = final velocity, u = initial velocity, a = acceleration, t = time.

From the question,

Given: u = 0 m/s(at rest), a = 0.2 m/s², t = 5 minutes = (5×60) = 300 s

Substitute these values into equation 1

v = 0+0.2(300)

v = 60 m/s.

Also for distance,

Applying,

s = ut+1/2at²................ Equation 2

Where s = distance travelled.

subtitute thes values above into equation 2

s = (0×300)+(0.2×300²)/2

s = 9000 m

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.