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devishri1977

Answer:

42.39 sq.cm

Step-by-step explanation:

Ф = 135°

r  = 6 cm

Area of the sector = [tex]\frac{theta}{360}*\pi *r^{2}\\[/tex]

  [tex]= \frac{135}{360}* 3.14 *6 * 6\\\\= \frac{135}{10}*3.14\\\\= 27 * 1.57\\\\=42.39[/tex]

The area of sector bounded by 135 ° arc is 42.42 cm ².

Step-by-step explanation:

Given :-

Radius of the circle , r = 6 cm

Angle of the circle, θ = 135 °

To Find :-

Area of circle bounded by a 135 ° arc.

Solution :-

We know that

[tex]\small \sf \: Area \: of \: sector \: = \frac{θ}{360} \: \times \pi \times r {}^{2} \\ [/tex]

Substitute the values of r and θ , we get

Area of sector =

[tex]\small \sf \: Area \: of \: sector \: = \frac{135 °}{360} \: \times \pi \times {6cm}^{2}\\ [/tex]

[tex]\small \sf \: Area \: of \: sector \: = \frac{135°}{360} \: \times \frac{22}{7} \times 6cm \times 6cm \\ \\ \small \: \sf Area \: of \: circle \: = \frac{135}{360} \times \frac{22}{7} \times 36cm {}^{2} \\ \sf \: \: = \frac{135}{10} \times \frac{22}{7} \\ \sf \: = 42.42cm \: {}^{2} [/tex]

Therefore, The area of sector bounded by 135 ° arc is 42.42 cm ².

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