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Sagot :
Answer:
y = 31 when x = 5
Step-by-step explanation:
We are to evaluate (not solve) the function y = 6 x + 1 for x = 5.
Substituting 5 for x in y = 6x + 1, we get
y = 6(5) + 1 = 31
y = 31 when x = 5
Problem:
Find the solution of y = 6x + 1 when x = 5.
[tex] \quad\quad \quad\quad\tt{y = 6x + 1}[/tex]
[tex] \quad\quad \quad\quad\tt{y = 6(5) + 1}[/tex]
[tex] \quad\quad \quad\quad\tt{y = 30 + 1}[/tex]
[tex] \quad\quad \quad\quad \boxed{\tt{y = 31}}[/tex]
Hence, the final answer is:
[tex]\quad\quad \quad\quad \boxed{\tt \color{green}{y = 31}}[/tex]
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