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Sagot :
Answer:
21
Step-by-step explanation:
Algebraic Method: Find Z-Score for Exam A
[tex]z=\frac{x_A-μ_A}{σ_A}[/tex]
[tex]z=\frac{510-550}{40}[/tex]
[tex]z=\frac{-40}{40}[/tex]
[tex]z=-1[/tex]
Addison scored 1 standard deviation below the mean.
Plug Z into formula for Exam B:
[tex]-1\frac{x_B-26}{5}[/tex]
[tex]-5=x_B-26[/tex]
[tex]21=x_B[/tex]
Addison would have to score 21 on Exam B
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