Answer:
The current through R2 is 0.078125 amperes.
Explanation:
Ohm's law is the relationship between electrical conductors and their resistance, which establishes that the current that passes through the conductors is proportional to the voltage applied to them.
Ohm's Law relates the magnitudes of voltage, resistance, and intensity as follows:
V=I*R
where V is the electric potential in volts, I is the current in amperes, and R is the resistance in ohms.
R1 has a 0.200 amperes current flowing through it and a resistante of 25 ohms.
So:
V=0.200 amperes* 25 ohms
Solving:
V=5 volts
Now, for resistance R2 you know the value of the voltage (5 volts) and the value of its resistance R2 = 64 ohms. So:
5 volts= I* 64 ohms
Solving:
[tex]I=\frac{5 volts}{64 ohms}[/tex]
I= 0.078125 amperes
The current through R2 is 0.078125 amperes.
Answer:
the current through R₂ is 0.078 A
Explanation:
Given;
resistance of the first resistor, r₁ = 25 ohms
resistance of the second resistor, r₂ = 64 ohms
current through the first resistor, I₁ = 0.2 A
The voltage passing through each resistor is constant since they are connected parallel to each other.
V = I₁R₁ = I₂R₂
[tex]I_2 = \frac{I_1R_1}{R_2} \\\\I_2 = \frac{0.2 \times 25}{64} \\\\I_2 = 0.078 \ A[/tex]
Therefore, the current through R₂ is 0.078 A
