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Find the geometric series of a geometric sequence where a= 294 and common ratio of
seven for a6, through a10.


Sagot :

ANSWER =6(7)^(N-1)

A0 = 6
A1 =6(7)^0
A2= 6(7)^1
A3 = 6(7)^2 = 294
A4 = 6(7)^3= 2058
A5 = 6(7)^4
A6 = 6(7)^5 = 100,842 = about 100K=10% of a million
....
A7 = 6(7)^5 = 242,121,642 = about a quarter mill
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